Coordinate description of motion
Plane motion of a point is given by x = x(t), y = y(t). The classic first problem of theoretical mechanics: find the trajectory and all kinematic quantities at time t₁.
Solution steps
- Trajectory. Eliminate t. If one coordinate is linear in t, express t and substitute. With sin and cos of the same argument use sin²u + cos²u = 1 (ellipse or circle); with cos 2u and sin u use cos 2u = 1 − 2sin²u (parabola).
- Velocity. Components are first derivatives: vₓ = ẋ, v_y = ẏ; v = √(vₓ² + v_y²), tangent to the path.
- Acceleration. Second derivatives: aₓ = ẍ, a_y = ÿ; a = √(aₓ² + a_y²).
- Tangential acceleration aτ = dv/dt = (vₓaₓ + v_ya_y)/v; positive — speeding up, negative — slowing down.
- Normal acceleration an = √(a² − aτ²) = |vₓa_y − v_yaₓ|/v, pointing to the centre of curvature.
- Radius of curvature ρ = v²/an.
Example
x = 4sin(πt/6), y = −3cos(πt/6) + 4 (cm), t₁ = 1 s. From sin² + cos² = 1 the path is the ellipse x²/16 + (y − 4)²/9 = 1. Press «Example» to see all steps and the plot.
Check: aτ² + an² must equal a², and v must be tangent to the path.